二元搜尋法需要先把要搜尋的數列先排序,由小到大,規則是先取前後二索引數,相加除二,也就是取中間數當索引值,然後跟要搜尋的數字做比較,如果一樣就是找到了,如果中間的數比要搜尋的數大,代表要搜尋的數在左邊數列,右邊數列則放棄,相反之,如果中間數比要搜尋的數小,代表要搜尋的數在右邊數列,左邊數列則放棄。
演算過程的畫面如下程式畫面:
數列串是1,2,3,4,5,6,7,8,9,10,11,12,然後要查詢4這個數字


演算法程式碼如下:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ConsoleApplication1
{
class Program
{
private static int binarySearch(int[] list,int SearchKey)
{
int left = 0 ;
int right = list.Length;
while (left <= right)
{
int mid = (left + right) / 2;//取中間位子當基準
if (list[mid] == SearchKey)
{
return mid;//找到的index值
}
else
{
if (list[mid] < SearchKey)//在右邊的數列
{
left = mid + 1;
}
else//在左邊的數列
{
right = mid - 1;
}
}
}
return -1;//找不到時
}
static void Main(string[] args)
{
int[] list = { 1,2,3,4,5,6,7,8,9,10,11,12};
Console.WriteLine("原始數字串");
for (int i = 0; i < list.Length; i++)
{
Console.Write(list[i]+" ");
}
Console.WriteLine("\r\n請輸入要查詢的數字:");
int SearchKey = Convert.ToInt32(Console.ReadLine());
int index = binarySearch(list,SearchKey);
if (index == -1)
{
Console.WriteLine("找不到資料!");
}
else
{
Console.WriteLine("查到的索引位置:"+index);
}
Console.ReadLine();
}
}
}
執行結果如下:

執行動作過程的程式原始碼如下:
Form1
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace WindowsFormsApplication1
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
string value = this.textBox1.Text;
string search = this.textBox2.Text;
if (value.Equals(""))
{
MessageBox.Show(this, "請先輸入數字串");
}
else if (search.Equals(""))
{
MessageBox.Show(this, "請先輸入要查詢數字");
}
else
{
string[] strnum = value.Split(new Char[]{','});
int[] num = new int[strnum.Length];
for (int i = 0; i < num.Length; i++)
{
num[i] = System.Convert.ToInt32(strnum[i]);
}
int iSearch = System.Convert.ToInt32(search);
Form2 form2 = new Form2(num,iSearch);
form2.Visible = true;
}
}
}
}
Form2
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
namespace WindowsFormsApplication1
{
public partial class Form2 : Form
{
private int[] num;
private int search;
public Form2()
{
InitializeComponent();
num = new int[0];
search = -1;
}
public Form2(int[] num,int search)
{
InitializeComponent();
this.num = num;
this.search = search;
}
protected override void OnPaint(PaintEventArgs e)
{
Font font = new Font("Verdana",14);
Font font_word = new Font("Verdana", 12);
SolidBrush brush_check = new SolidBrush(Color.Red);
SolidBrush brush = new SolidBrush(Color.Blue);
SolidBrush brush2 = new SolidBrush(Color.Green);
SolidBrush brush_word = new SolidBrush(Color.Black);
Graphics g = e.Graphics;
int top = 20;
//初始左右二邊
int left = 0;
int right = num.Length-1;
{
int j = 1;
top = 20;
while(left<=right)//找不到時會成立
{
g.DrawString("找第 " + (j ) + " 次", font_word, brush_word, 0, top);
j++;
int mid = (left + right) / 2;//取中間點
if (num[mid] == search)
{
g.DrawString(num[mid].ToString(), font, brush_check, 30 * mid + 90, top);//找到
g.DrawString("找到了", font, brush_check, 30 * (mid + 1) + 90, top);//找到
return;
}
else
{
//中間值有可能在右邊或左邊
for (int i = left; i < mid + ((num[mid] < search) ? 1 : 0); i++)
{
g.DrawString(num[i].ToString(), font, brush, 30 * i + 90, top);
}
//中間值有可能在右邊或左邊
for (int i = right; i > mid-((num[mid] < search) ? 0 : 1); i--)
{
g.DrawString(num[i].ToString(), font, brush2, 30 * i + 90, top);
}
//一次切一半
if (num[mid]< search)
{
g.DrawString("左邊不要", font, brush, 30 * (right+1)+90 , top);
left = mid + 1;
}
else
{
g.DrawString("右邊不要", font, brush, 30 * (right + 1)+90, top);
right = mid - 1;
}
}
top = 20 * j;//印到下一行
}
}
g.DrawString("找不到", font, brush_check, 0, top+20);//找到
}
}
}
有個小BUG哦~演算法部份第13行應該是int right = list.Length – 1;